fdesalvo
Hero Member
- Messages
- 3,609
Just trying to wrap my mind around it. As a guy who loved physics in school, it's quite interesting. If there is no fretboard left beneath the strings, how can we presume the radius is continuing to flatten as it reaches a termination point with X radius? You are basically off of the "cone", right? Shouldn't the radius be calculated by taking the difference in radius between the last fret and the saddles into account? Now, call me crazy; this may be the 100mg of dipehydramine I'm currently on. :icon_biggrin:
LMAO re the "corner" comment! If the tuning is done on open strings, then the only two radii in contention would be that of the nut and bridge!
LMAO re the "corner" comment! If the tuning is done on open strings, then the only two radii in contention would be that of the nut and bridge!
Jumble Jumble said:This would mean that the strings changed radius steadily until the 22nd fret, and then somehow stayed at the same radius until the bridge. That would mean that when you tuned up your guitar, the strings would have a corner in them above the 22nd fret!fdesalvo said:If the last fret is 16" and the saddle radius is set to 16", then I would imagine you have a 16" straight radius from that last fret to the bridge, correct?