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schematic help

big bob

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I was wondering if anyone could help me convert this schematic into a wiring diagram. I pretty sure I know how to wire it but would love to see a picture.
the set up is two humbuckers and a hum sized p-90 all wired to push pulls for on/off
three volume one tone
the three way switch become a selector for a kill and a coil tap
thanks
 

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I have this VVVT diagram with on/off switches.
5383313703_e18d24dbc6_o.png


What do you mean by "the three way switch become a selector for a kill and a coil tap?"
If you want, you can do DPDT On-On-On (A.K.A. SP3T) switches wired as series/split coil (North or south coil.)/off or full wind/tapped wind/off for tapped single coils.
 
the three way selects between bridge/ bridge coil tap/ kill the schematic is at the bottom of my post (a pdf) take a look.
Thanks
 
big bob said:
the three way selects between bridge/ bridge coil tap/ kill the schematic is at the bottom of my post (a pdf) take a look.
Thanks

The diagram is a little different than the diagram I posted above.
It has pros and cons.

The switches come after the volumes, so you can wire the wiper terminals of the volumes as outputs, so the resistance against the pickups is constant. Traditionally guitars with multiple volumes and no switch are wired with the wiper terminal to the pickup hots, so that the volumes can function independently, but it causes a variable impedance load against the pickups when the volumes are adjusted. Wiring the wiper terminal to the output is preferable when possible, but be careful about rolling the volumes down too much, as it drops the output impedance.

Also, be mindful that if all three pickups are turned off with the switches, the output impedance will be infinite, not zero, so you will need to use the master killswitch, or you may experience an "open cable buzz."

As I understand it, you want that schematic translated into a wiring diagram to follow?
 
Btw, a flaw in that diagram is that the master killswitch simply interrupts the signal path, instead of grounding the output. This is a BAD way to wire a killswitch, as it leaves you with an infinite output impedance, instead of zero. In this particular case, there is a tone control which always operates parallel to the jack, but the output impedance will still be very high for frequencies below the cutoff point for the tone control.

Assuming you have passive pickups, the best way to wire a killswitch is to short the output entirely. With active pickups, you interrupt the signal path and ground the output.
 
the pickups are passive, I would prefer to wire it so that up is on..
I really appreciate your help.. this is all new to me
Thanks
 
line6man said:
Btw, a flaw in that diagram is that the master killswitch simply interrupts the signal path, instead of grounding the output. This is a BAD way to wire a killswitch, as it leaves you with an infinite output impedance, instead of zero. In this particular case, there is a tone control which always operates parallel to the jack, but the output impedance will still be very high for frequencies below the cutoff point for the tone control.

Assuming you have passive pickups, the best way to wire a killswitch is to short the output entirely. With active pickups, you interrupt the signal path and ground the output.

I've been thinking about this ever since I read it.  line6man, I wonder if you might elaborate a little.  What I understand is that the best way to wire a killswitch is to take something like an SPST switch, run the signal path across one pole, and the ground across the other, so that when you switch/press/whatever, it makes a connection between the signal path and the ground, causing a short circuit that will momentarily kill the output.  Right?  And what would be the consequence of doing it the other way?  "Infinite output impendance" to me sounds like "crossing the beams" in Ghostbusters.  It sounds like a bad thing, but what would happen?  Would it cause a rift in the universe or something?

Thanks.
 
Solid said:
line6man said:
Btw, a flaw in that diagram is that the master killswitch simply interrupts the signal path, instead of grounding the output. This is a BAD way to wire a killswitch, as it leaves you with an infinite output impedance, instead of zero. In this particular case, there is a tone control which always operates parallel to the jack, but the output impedance will still be very high for frequencies below the cutoff point for the tone control.

Assuming you have passive pickups, the best way to wire a killswitch is to short the output entirely. With active pickups, you interrupt the signal path and ground the output.

I've been thinking about this ever since I read it.  line6man, I wonder if you might elaborate a little.  What I understand is that the best way to wire a killswitch is to take something like an SPST switch, run the signal path across one pole, and the ground across the other, so that when you switch/press/whatever, it makes a connection between the signal path and the ground, causing a short circuit that will momentarily kill the output.  Right?  And what would be the consequence of doing it the other way?  "Infinite output impendance" to me sounds like "crossing the beams" in Ghostbusters.  It sounds like a bad thing, but what would happen?  Would it cause a rift in the universe or something?

Thanks.

An infinite output impedance is like an open guitar cable buzzing.
Unplug your cable and observe the noise you hear coming from your rig.
 
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